Ok... let's say I only want titles and pub date... this is teh default XSL file:

 <?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="html" indent="yes"/>
  <xsl:param name="limit">3</xsl:param>
  <xsl:param name="ItemsToShow"/>
  <xsl:param name="ShowItemDetails"/>
  <xsl:param name="ShowItemDate"/>
  <xsl:param name="Locale"/>
  <xsl:template match="rss">
    <xsl:for-each select="channel/item[position()&lt;=$ItemsToShow or $ItemsToShow&lt;1]">
      <p class="DNN_News_ItemLink">
        <a href="{link}" target="_main">
          <xsl:value-of select="title"/>
        </a>
      </p>
      <xsl:if test="$ShowItemDate='true'">
        <p class="DNN_News_ItemDate">
          <xsl:value-of select="pubDate"/>
        </p>
      </xsl:if>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet> 

 I added this line:

<xsl:param name="limit">3</xsl:param>

 It ignore this and displays everything - not just the three... what I am doing wrong here? Thanks for the insight.

Pingle thanks for the advice... but I tried this and it still shows everything... can anyone explain how to only allow this to only show three items:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="html" indent="yes"/>
  <xsl:param name="limit" select="3"/>
  <xsl:param name="ItemsToShow"/>
  <xsl:param name="ShowItemDetails"/>
  <xsl:param name="ShowItemDate"/>
  <xsl:param name="Locale"/>
  <xsl:template match="rss">
    <xsl:for-each select="channel/item[position()&lt;=$ItemsToShow or $ItemsToShow&lt;1]">
      <p class="DNN_News_ItemLink">
        <a href="{link}" target="_main">
          <xsl:value-of select="title"/>
        </a>
      </p>
      <xsl:if test="$ShowItemDate='true'">
        <p class="DNN_News_ItemDate">
          <xsl:value-of select="pubDate"/>
        </p>
      </xsl:if>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>
 

I did this and got the following error on the page where the News module is placed:

System.Xml.Xsl.XslLoadException XSLT compile error.

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="html" indent="yes"/>
  <xsl:param name="ItemsToShow">3</xls:param>
  <xsl:param name="ShowItemDetails"/>
  <xsl:param name="ShowItemDate"/>
  <xsl:param name="Locale"/>
  <xsl:template match="rss">
    <xsl:for-each select="channel/item[position()&lt;=$ItemsToShow or $ItemsToShow&lt;1]">
      <p class="DNN_News_ItemLink">
        <a href="{link}" target="_main">
          <xsl:value-of select="title"/>
        </a>
      </p>
      <xsl:if test="$ShowItemDate='true'">
        <p class="DNN_News_ItemDate">
          <xsl:value-of select="pubDate"/>
        </p>
      </xsl:if>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>

 Sorry this is not my area of expertise...