I am using the following rss feed:

http://www.hallindsey.org/thehallindseyreport.rss

My xsl looks like this:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes"/>
<xsl:param name="TITLE"/>
<xsl:template match="rss">
  <!-- Do not show channel image -->

  <xsl:for-each select="channel/item">
  <xsl:if test="position() &lt; 6">
   <BR></BR>
   <strong>
    <a href="{link}" target="_new">
     <xsl:value-of select="title"/>
    </a>
   </strong>
   <br></br>
   <!-- only display markup for description if it's present -->
   <xsl:value-of disable-output-escaping="yes" select="description"/><xsl:text> </xsl:text>
   <I>
    <xsl:value-of disable-output-escaping="yes" select="substring(pubDate,1,16)"/>
   </I>
   <BR></BR>
  </xsl:if>
  </xsl:for-each>
</xsl:template>
</xsl:stylesheet>

This same XSL file is being used for othe feeds and is sorting most current first.... however, on this one it is not sorting correctly... Can someone point me in the right direction? Thanks.

Can someone help with this? I have no idea what I am doing.......

Ok, if you really want the solution, you'll have to take a look at my blog where I provide a working XSL that illustrates how to sort a feed that renders in the new module.  The solution involves adding a custom namespace, and using an element that the module creates pubDateParsed to actual provide the key to sort on.

Cheers