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HomeHomeDNN Open Source...DNN Open Source...Module ForumsModule ForumsXMLXMLHow to interpret not really typical XML file in XML moduleHow to interpret not really typical XML file in XML module
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7/20/2009 9:35 AM
 
JS

Joined: 6/19/2009
Posts: 1

Hello, I would really apreciate any help with following case. I have an XML file produced by one web service, this is an example:

<?xml version="1.0" encoding="utf-8"?>
<Result>
  <SCategory Id="0">
    <SCategory Code="" Name="" />
  </SCategory>
  <SCategory Id="2">
    <SCategory Code="AUDI" Name="AUDIO/VIDEO" />
  </SCategory>
</Result>

So within Result tag there are information about two SCategories with elements Id, Code and Name. I want to put all of these elements to table. I was trying to do that with following XSL file:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="/">
  <html>
  <body>
  <h2>Kategorie:</h2>
    <table border="1">
      <tr bgcolor="#9acd32">
      <th>Id</th>
      <th>Code</th>
      <th>Name</th>
      </tr>
      <xsl:for-each select="Result/SCategory">
      <tr>
        <td><xsl:value-of select="Id"/></td>
        <td><xsl:value-of select="Code"/></td>
        <td><xsl:value-of select="Name"/></td>
      </tr>
      </xsl:for-each>
    </table>
  </body>
  </html>
</xsl:template>
</xsl:stylesheet>

Only what I get is header of the table and two empty rows, so it looks like XML parser can find SCategory elements, but there's probably problem with interpreting of the rest of tags.

Does anybody idea what I am doing wrong? I was trying to change XSL file many times, but still without positive result....

Thanks a lot, Jan
 
New Post
7/20/2009 11:13 AM
 
Steve Fabian


Steve Fabian's Avatar

Joined: 3/4/2003
Posts: 2111

Your XSL would work if the original XML source looked like this... which of course it does not.

<?xml version="1.0" encoding="utf-8"?>
<Result>
  <SCategory>
    <Id>0</Id>
    <Code></Code>
    <Name></Name>
  </SCategory>
  <SCategory>
    <Id>1</Id>
    <Code>AUDI</Code>
    <Name>AUDIO/VIDEO</Name>
  </SCategory>
</Result>


So, based on the XML you posted, try this...

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 
<xsl:template match="/">
  <html>
  <body>
  <h2>Kategorie:</h2>
    <table border="1">
      <tr bgcolor="#9acd32">
      <th>Id</th>
      <th>Code</th>
      <th>Name</th>
      </tr>
      <xsl:for-each select="Result/SCategory">
      <tr>
        <td><xsl:value-of select="@Id"/></td>
        <td><xsl:value-of select="SCategory/@Code"/></td>
        <td><xsl:value-of select="SCategory/@Name"/></td>
      </tr>
      </xsl:for-each>
    </table>
  </body>
  </html>
</xsl:template>
</xsl:stylesheet>


 Steve Fabian
e: steve.fabian@gooddogs.com
w: http://www.gooddogs.com
 
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